Which Of The Following Platonic Solids Is Also A Cone


Which Of The Following Platonic Solids Is Also A Cone

A container in the shape of a hollow cone of semi-vertical angle 30 is held with its vertex pointing downwards. Water is poured into the cone at rate of 70cm s.find the rate at which the depth of water in the cone is increasing when the depth of the water is 9 cm

Daftar Isi

1. A container in the shape of a hollow cone of semi-vertical angle 30 is held with its vertex pointing downwards. Water is poured into the cone at rate of 70cm s.find the rate at which the depth of water in the cone is increasing when the depth of the water is 9 cm


Jawaban:

☺☺

Penjelasan dengan langkah-langkah:

ga ngerti? coba pake b indo


2. A ship tows an instrument in the form of a 30° cone, point first, at 7.5 m/s in seawater. if the base of the cone has a diameter of 2.20 m, calculate the force in the cable to which the cone is attached.


Jawaban:

Sebuah kapal menarik instrumen berbentuk kerucut 30°,

titik pertama, pada 7,5 m/s di air laut. jika alas kerucut

memiliki diameter 2,20 m, hitung gaya pada kabel untuk

yang kerucut terpasang.

Penjelasan:

cuma bisa nolong nerjemahin doang


3. what's the definition of platonic​


Jawaban:

Platonicmeans to have share a close bond with another person, yet it's not se*ual like romantic relationships. Platonic relationships are usually bonds with friends.

Hopethishelps~


4. look at the metal pedulum. the metal pendulum consists of a cone and a half sphere . if the radius of the half sphare is 10 cm and the slant height (apothem) of the cone is 20 cm , the surface area of the pendulum is....cm2


the surface area of pendulum =
[tex]2\pi. {r}^{2} + \pi.r.s[/tex]
= 2. 3,14. 100 + 3,14 . 10.20
= 628 + 628
= 1256 cm2

5. The metal pendulum consist of a cone and a half sphere if the radius of the half sphere is10 cm and the slant height (apothem) of the cone is 20 cm the surface area of the pendulum is


lpkerucut=phi×r(r+s)
=3.14×10(10+20)
=31.4×30
=942cmkubik
lp1/2bola=2phi×r kuadrat
=2×3.14×10×10
=624 cm kubik
surface area of pendulum =942+624
=1566cm kubik

6. 1. Cari isipadu bagi setiap pepejal berikutFind the volume of the following solidsa)3 crn2 cm6 cm​


Jawaban:

V balok=p×l×t

=6 cm × 2 cm × 3 cm

=36 cm³

maaf klo salah

Jawab:

36cm³

RUMUS:

6x3x2 = 36 cm³


7. The cone has the height 24 cm and the area of base is 154 square centimeters. The volume of cone with is....


Volume = 1/3 × area×height = 1/3×154×24=1232 cm³

So, the volume of cone is 1232 cm³

Maaf ya kalau salah


8. plss siapapun bantu by first identifying the base, find the volume and surface area of each of the following solids​


Penjelasan dengan langkah-langkah:

Identifikasi bentuk alasTentukan volumeTentukan luas permukaan

SOAL NOMOR 3A

Merupakan bangun ruang prisma segitiga maka alasnya adalah segitiga

1. Tentukan volume

Volume prisma = luas alas x tinggi prima

Volume prisma = 12 x 16 x 14

Volume prisma = 2688 cm³

2. Tentukan luas permukaan

Luas permukaan = 2 x luas segitiga + luas ketiga persegi

Luas permukaan = 2 x 16 x 12 + 14 x 20 + 16 x 14 + 12 x 14

Luas permukaan = 1056 cm²

SOAL NOMOR 3B

1. Tentukan volume

volumenya adalah jumlah 5 volume balok. Karena bangun ruang tersebut terbentuk dari kumpulan balok.

Volume = 5 x 3 x 4 x 5

Volume = 300 cm³

2. Tentukan luas permukaan

Luas permukaan = 10 x 4 x 5 + 4 x 3 x 5 + 2 x 3 x 4 + 2 x 3 x 4

Luas permukaan = 308 cm²

SOAL NOMOR 3C

Merupakan bangun ruang prisma segitiga maka alasnya adalah segitiga

1. Tentukan volume

Volume prisma = luas alas x tinggi prima

Volume prisma = 6 x 8 x 14

Volume prisma = 672 cm³

2. Tentukan luas permukaan

Luas permukaan = 2 x 6 x 8 + 14 x 8 + 14 x 6 + 14 x 10

Luas permukaan = 432 cm²

SOAL NOMOR 3D

1. Tentukan volume

Volume = p x l x b tiga balok

Volume = 21 x 10 x 5 + 2 x 7 x 6 x 10

Volume = 1890 cm³

2. Tentukan luas permukaan

Luas permukaan = luas permukaan balok + luas dua persegi panjang

Luas permukaan = 2 x 21 x 10 + 2 x 15 x 10 + 2 x 7 x 10

Luas permukaan = 860 cm²


9. According to the passage, which of the following is true about water cycle?a. The water cycle is also known as the rain cycleb. The water cycle is also known as the recyclec. The water cycle is also known as the hydro carbond. The water cycle is also known as the hydrologic cyclemohon bantuannya ​


Jawaban:

a. The water cycle is also known as the rain cycle


10. 1. The radius of a cylinder's base is 7 cm and the height of the cylinder is 15 cm. The total surface area of the cylinder is ……. Cm2 ( taking π≈ 22/7 ) * 2.The diameter of a cone's base is 10 cm. If the slant height of the cone is 13 cm, the volume of the cone is ……. Cm3. ( taking π≈ 3.14 ) * 3.The volume of a cone is 462 cm3. If the height of the cone is 9 cm, the radius of the cone base is ..... Cm * 4.The volume of a sphere is 288π cm3. The total surface area of the sphere is …. Cm2. ( state your answer in π ) * 5.The first cylinder has a radius of 4 cm and its height is 10 cm. The second cylinder has a radius of 6 cm and its height is 8 cm. The ratio of volume of both cylinders is ……. *


Penjelasan dengan langkah-langkah:

1. r = 7cm

h = 15 cm

A =2πrh

= 2 x 22/7× 7cm x 15cm

= 660cm²

2. D = 10 cm

r = 5cm

s = 13 cm

find h use pitagoras

h² = 13²cm² - 5²cm²

=144cm²

h =√144cm² = 12cm

V =⅓πr²h

= ⅓ x3.14 x 5²cm² x 12cm

= 314cm³

3. Vcone = 462cm³

h = 9cm

Vcone= ⅓πr²h

462cm³ = ⅓ π r² x 9 cm

r² = 462cm³ / 3π

= 49cm²

r = √49cm² = 7cm

4. Vsphere = 288π cm³

⅓x4πr³ = 288π cm³

r³ = 288π cm³ x ¾π

= 216cm³

r = ³√216cm³ = 6cm

A = 4πr²

= 4π x 6²cm²

= 144π cm²

5. r¹ = 4 cm

h¹ = 10 cm

r2 = 6 cm

h2 = 8 cm

cylinder

V1 = V2

πr1²h = πr2²h ==>divide by π

r1²h = r2²h

4²cm²x10cm = 6²cm²x 8cm

160 cm ⅔= 288cm³

= 5 : 9


11. the volume of cone is... cm


the rumus
= ⅓. πr²t
= …… cm

12. 18. Which one is not the kind of shape?a. Rhombusb. YellowC. Coned. Pyramid​


Jawaban:

A. Rhombus

semoga membantu✨✨

dan jangan lupa untuk follow aku ✨✨yah entar ku folback✨✨ ok

dan jadikan aku yang terbaik

i love you❤❤

yang sudah dukung aku✨✨✨

lopyu lopyu

jawaban:

jawabannya : b. yellow

penjelasan:karna yellow bukan bentuk


13. Height of cone=20cm Radius of cone=14cm What is the CURVED surface area of the cone? 30 POINT!!!


꒷꒦˖˚˳⊹︶︶꒷꒦ ✧ ⊹ ₊⁀➷

┊ ┊ ┊┊┊. ➶ ˚ Jawaban dibawah

┊ ┊ ┊ ˚✧

┊ ˚➶ 。˚ ☁︎

☁︎

Radius=jari jari

Height=tinggi

cone=kerucut

surface area=luas permukaan

t=20cm

r=14cm

Sisi

C²=a²+b²

C²=196+400

C²=596

C=2√149

Lp=Π×r×(r+s)

Lp

[tex] = \frac{22}{7} \times 14 \times (14 + 2 \sqrt{149} ) \\ = 44 \times (14 + 2 \sqrt{149}) \\ = (616 + 88 \sqrt{149}) {cm}^{2} [/tex]

┈➤ . . ⇢ ˗ˏˋ⌦ ⓜⓞⓖⓐⓟⓐⓗⓐⓜ ..♡ˎˊ˗ ꒰✈꒱   

╭─────────

┊╭─────────

┊✿꒷꒦ Makasi

╰─────────

★ . ꜝꜞ ᳝ ࣪ Semoga membantu!  ʬʬ

[tex] \boxed{\tt{ \green{answered \: by \: duone}}}[/tex]


14. ## Quiz #15 ##• midnight quiz• English edition• big point• no spam________________________Figure 1 shows a paperweight made from a hollow hemisphere and a hollow cone.The paperweight contains sand so that the sand exactly fills the hemisphere. The radius of the hemisphere is equal to the radius of the base of the cone. The height of the cone is 15 cm and the volume of the cone is 180π cm3.Figure 2 shows the paperweight after it has been turned upside down. The height of the sand in the cone is h cm. Find the value of h!​


Jawab:

13.95 cm

Penjelasan dengan langkah-langkah:

the volume of the cone =

⅓× π r². h = 180 π

⅓×π r²×15 = 180 π

(eliminate π)

=> 5r² = 180

r² = 180/5 = 36

r=√36 = 6 cm

the volume of the sand = ½×4/3 π r³

= ⅔× π ×6³ = 144π cm³

the ratio of the volume :

144π/180π = 0.8

so the value of h = ³√0.8 x 15 = 0.93× 15

= 13.95 cm


15. A wafer cone is completly filled with 150.72 cm3 of icecream. The top of icecream is in the shape of hemisphere. Given that the diameter of the cone is 6 cm, find its height



[tex]volume = \frac{1}{3} (\pi {r}^{2}) h \\ 150.72 = \frac{1}{3} (3.14 \times {3}^{2} )h \\ 150.72 = (3.14 \times 3)h \\ 150.72 = 9.42h \\ h = \frac{150.72}{9.42} \\ h = 16[/tex]
the height of cone is 16cm.

16. What is the stucture of solids, liquids, and gases?


The structure of a solid is a molecule that is tightly arranged and does not change. Example:

- ice cube

- stone

- etc

The structure of a liquid is a molecule that is less dense / starting to be far apart. Example:

- water

- oil

- Syrup

- etc

The structure of a gas is a molecule that is very tenuous and does not coalesce. Example

- oxygen

- steam

- etc

Sorry if it's wrong. I'm still a beginner. I hope this helps :)


17. 1.inter molecular cohesive for in the fluids is a. less than of the solids b. more than that of the solids c. equal to that of the solids d. unpredic table Note:include with reason


Penjelasan:

a.less than of the solids


18. Look at the metal pendulum. The metal pendulum consists of a cone and a half sphere. If the radius of the half sphere is 10 cm and the slant height(apothem) of the cone is 20 cm, the surface area of the pendulum is....cm²


Lp pendulum = Lp 1/2 bola + Lp kerucut tanpa alas
L = 1/2 . 4 . phi . r² + phi. r . s
L = 2 . 3,14 . 10² + 3,14 . 10 . 20
L = 1256cm²

19. the diameter of the cone above is?tolong jawab:)​


Jawaban:

⇒204,1

Penjelasan dengan langkah-langkah:

rumus : phi×r×s

⇒diameter = 10

r = 5

t = 12

s = akar r^2 + t^2

= akar 5^2 + 12^2

= akar 25 + 144

= akar 169

= 13

Luas selimut kerucut = phi.r.s

= 3.14 × 5 × 13

= 204,1

semogamembantu^^


20. The volume of cone is ... cm3


Bangun Ruang

Volume of cone = 1/3 x π x r x r x h
= 1/3 x π x r² x h

Artinya,
Volume kerucut = 1/3 x π x r x r x t
= 1/3 x π x r² x t

Keterangan:
r = radius (jari-jari)
h = high (tinggi)

*semoga membantu. sukses selalu ^_^

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Which Of The Following Platonic Solids Is Also A Cone Which Of The Following Platonic Solids Is Also A Cone Reviewed by Romano on September 16, 2022 Rating: 5

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