a boy thrown up a ball vertically upward with the speed of 3 m/s. what is the maximum height can reached if acceleration of gravity is 9,8 m/s ?
1. a boy thrown up a ball vertically upward with the speed of 3 m/s. what is the maximum height can reached if acceleration of gravity is 9,8 m/s ?
[tex] v_{o} = 3m^{2} \\ g=9,8m/ s^{2} \\ \\ h_{maks} ....? \\ \\ h_{maks} = \frac{ v_{o} ^{2} }{2g} \\ \\ h_{maks} = \frac{(3)^{2} }{2x9,8} \\ \\ h_{maks} = \frac{9}{19,6} \\ \\ h_{maks} =0,45 m[/tex]
2. The average average height of a good is 142 cm theheightis 138 cm. what is the height of the other girls?
Jawab:
Penjelasan dengan langkah-langkah:
Diketahui :
Rata-rata tinggi perempuan = 142 cm
x₁ = tinggi perempuan pertama = 138 cm
Ditanya : x₂
Jawab :
Rata-rata
=> (x₁ + x₂ ) / 2 = 142
=> (138 + x₂ ) = 2 * 142 = 284
=> x₂ = 284 - 138 = 146 cm
Tinggi perempuan kedua = 146 cm
3. The base AB is related to the height _______The base CB is related to the height _______
Jawaban:
-FB
-CA/FA
Penjelasan:
4. Hasan is designing a gate for a minimalist type of house. The actual length and height of the gate is 6 m and 2 m. If the length of the gate on the sketch is 15 cm, then the height of the gate on the sketch is...
Jawab:
Height gate on the sketch = 5 cm
Penjelasan dengan langkah-langkah:
example;
Height = H
Length = L
no. 1 = real gate
no. 2 = gate on the sketch
Length gate on cm = 6 m x 100 cm
= 600 cm
Height gate on cm = 2 m x 100 cm
= 200 cm
Formula;
[tex]\frac{a1}{a2}[/tex] = [tex]\frac{b1}{b2}[/tex]
[tex]\frac{height 1}{height 2} = \frac{length 1}{length 2}[/tex]
[tex]\frac{height1}{200 cm}[/tex]= [tex]\frac{15 cm}{600 cm}[/tex]
height 1 = 200 x [tex]\frac{15}{600}[/tex]
height 1 = [tex]\frac{3.000}{600}[/tex]
height 1 = 5 cm
So, Height gate on the sketch = 5 cm
5. 29. If the model's height is 12 cm andthe scale is 1: 30, what is the realobject's height? *
Penjelasan dengan langkah-langkah:
model height = 12 cm
scale = 1:30
real height = 12 cm × 30 = 360 cm or 3,6 m
6. The height of the shadow is 5 cm and the real height of the object is 2 cm. The magnification of the object is
Jawaban:
M = 2,5 x
Penjelasan:
hi = 5 cm
ho = 2 cm
M = hi/ho = 5/2 = 2,5
Because the magnification of shadow is 2,5. So, the shadow is 2,5 times bigger than the object's height.
Explanation :Magnification (M) is the ability of an optical device to be able to change its actual size at its shadow. If the magnification of the shadow more than 1 ( M > 1), the size of shadow will bigger than the actual size. If the magnification is 1 (M = 1), the shadow will show actual size of the original. If the magnification is under 1 (M < 1), the shadow will smaller than the actual size. For calculate the magnification of the shadow, we can use this formula :
[tex] \boxed {\bold{|M| = |\frac{h'}{h}|}} \:\:\: or \:\:\:\boxed {\bold{|M| = |\frac{s'}{s}|}} [/tex]
If :
|M| = magnification => always positive h' = shadow height (cm or m) h = actual height (cm or m) s = distance the actual object to optical device (cm or m) s' = distance the shadow to optical device (cm or m) Work Steps :We know that :
h' = shadow's height = 5 cm h = object's height = 2 cmQuestion : |M| = magnification = ... ?
Answer :
[tex] |M| = |\frac{h'}{h}|[/tex]
[tex] |M| = |\frac{5}{2}| = \boxed {2,5}[/tex]
Detail Soal :Kelas : 8
Mata Pelajaran : Fisika
Materi : Bab 5 - Cahaya dan Alat Optik
Kata Kunci : Menghitung perbesaran bayangan
Kode Kategorisasi : 8.6.5
Pelajari Lebih Lanjut : How to calculate the eye lens focus https://brainly.co.id/tugas/29962629How to calculate the lens power https://brainly.co.id/tugas/299622037. The height of two building is 34 m and 29 m respectively. If the distance between the two building is 12 m, find the distance between their tops.
Jawaban:
13 m
Penjelasan dengan langkah-langkah:
Given :
Hight of first building is : AC = 34 m
Hight of Second building is : DE = 29 m
The distance between the two building is = 12 m
To find :
Distance between the tops of the building ,i.e., AE
Solution :
A
|＼x
B |___＼ E
C |_____| D
AB = 5 m, BC = 29m, & DE = 29m
BE = CD = 12 m
The distance between the tops of building be x m.
Using Pythagoras theorem
AE² = AB² + BE²
=> x² = 5² + 12²
=> x² = 25 + 144
=> x = √169 = 13 m
So, the distance between the tops of building is 13 m✓
Sources of : https://ask.learncbse.in/t/two-poles-of-heights-6-m-and-11m-stand-on-a-plane-ground/41757
8. The height of a father is 50% more than that of his son. By how many percent is the height of the son less than that of his father?
Jawaban:
Tinggi seorang ayah 50% lebih tinggi dari anaknya. Berapa persen tinggi anak laki-laki itu kurang dari ayahnya?
9. On a particular day, the height of the tide at East Coast Park was 0.8 m at dawnAt dusk the height of the tide increased by 40%. Find the height of the tide at duse
Jawab:
Hi, Oppung will answer your question.
Here it is.
The height of the tide at East Coast Park = 0.8 m at dawn
increased by 40% means:
[tex]40\% \times 0.8 \\= \frac{40}{100} \times 0.8\\=0.4 \times 0.8\\=0.32[/tex]
Therefore, the height of the tide at East Coast Park = 0.8 m + 0.32 = 1.12 m
at dusk.
10. the mean height of the 6 volleyball players in a team is 1.82 m. when the 3 reserve players are included, the mean height of the 9 players is 1.8 m. find the mean height of the 3 reserve players.
Penjelasan dengan langkah-langkah:
(6 x 1,82) + 3p = 9 x 1,8
10,92 + 3p = 16,2
3p = 16,2 - 10,92
3p = 5,28
p = 5,28/ 3 = 1,76
the mean height of the 3 reserve players
=1,76m
goodluck
11. Monica: "can you reach the stick on the branch of the tree?" masha: "no, the branch .... it is too high." the correct sentence to complete the dialogue is ....a. is reached b. had not been reached c. can't be reached d. can be reachede. will be reached
Jawaban
C. can't be reached
Penjelasan
no, the branch can't be reached. It is too high.
Artinya, "tidak, batangnya tidak bisa dipanjat. Itu terlalu tinggi"
12. 1. It is know that the ratio of the height of the house to the fence is 8 : 6 . if the difference between the height of the house and the fence is 4 meters . Then the height of each is ...
Penyelesaian:Solve:
8:6
fence
6/8-6×4
=6/2×4
=3×4
=12meters (fence)
House
8/8-6×4
=8/2×4
=4×4
=16meters(house)
[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
13. the volume of cuboid is 4032 cm³,the lenght is 32 cm and the height is 14 cm ,find the height
Volume = p x l x t
4032 = 32 x l x 14
4032 = 448l
l =4032/448
l = 9
jadi lebar nya adalah 9 cm
14. A building is drawn with a height of 20 cm. The scale of the image of the building is 1 : 105. The actual height of the building is ... m.
Jawab:
Penjelasan dengan langkah-langkah:
height = 20 cm
scale 1 : 105
actual height = 20 x 105 = 2100 cm = 21 m
15. every 45 metres height from the sea surface,the temperature decreased by 0,5C.if the temperature on the surface is 27C,what is the temperature on 3,600m height over the sea surface?
3600:45 l = 80
80x0.5 = 40
27-40 = ....
16. The base of a triangle is longer than twice its corresponding height by 1 cm. The area of the triangle is 105 cm?. Find the height of the triangle!butuh cepat
Jawaban:
52,5
Penjelasan dengan langkah-langkah:
105:2 sorry if wrong
Jawab:
The height of the triangle is 10 cm.
Penjelasan dengan langkah-langkah:
If the area, base and height of that triangle are notated by A, b and h, then it is known that:
A = (1/2)bh
b = 2h+1
So:
A = (1/2) × (2h+1) × h
A = (1/2) × (2h²+h)
2A = 2h²+h
2×105 = 2h²+h
210 = 2h²+h
2h²+h-210 = 0
(2h+21)(h−10)=0
2h+21=0 or h−10=0
h = -21/2 or h = 10
The positive solution is h = 10, so the height of the triangle is 10 cm.
Proof:
If the height is 10 cm, then the base equals to 21 cm (2×10 + 1 = 21).
The area of the triangle:
A = (1/2)bh = (1/2)(21)(10) = (1/2)(210) = 105 cm². (correct!)
17. the volume is 360cm3 the height is 5cm the width is 8cm, what is the length
Jawab:
9cm
Penjelasan dengan langkah-langkah:
Volume = Length x Width x Height
so, 360 = 8 x ? x 5
? = 360/(8x5)
= 360/40 = 9
Penjelasan dengan langkah-langkah:
V = Length ( L ) × Width ( W )× Height ( H )
360 = L × 8 × 5
360 = L × 40
360 : 40 = L
9 = L
So, the length of the block is 9 cm
18. The bullet is fired upwards at an initial speed of vo m/s. The height of the floor after t seconds is expressed by the function h(t) = 100 + 40t – 4t2. The maximum height that the ball can reach is...~-~nt: next time Mashi. Charissa is busy
the answer is...
100 m
why 100m?
.......
°"The bullet is fired upwards at an initial speed of vo m/s."
°"The height of the floor after t seconds is expressed by the function h(t) = 100 + 40t – 4t2."
asked???
The maximum height the ball can reach?
the answer is 100m.
hope it's useful ^^
19. The height of two plants is in the ratio 7:9.the height of the taller plant is 26 cm more than the height of the shorter plant.what is their total height?
s : t = 7 : 9 <=> 9s = 7t (s = shorter, t = taller)
t = s + 26
9s = 7t
9s = 7(s + 26)
9s = 7s + 182
2s = 182
s = 91
So
s + t
= s + s + 26
= 2s + 26
= 182 + 26
= 208 cm
◉‿◉
20. the base of a rectangular tank is 135 m2 the volume of the tank is 6.750 m³ therefore the height of the rectangular tank is
Volume of a rectangle = area of base . Height
= H = 6750 / 135
= h = 50 cm
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on
Desember 11, 2022
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