the sum of 3 even number is 90 the sum of the biggest and the smallest number is
1. the sum of 3 even number is 90 the sum of the biggest and the smallest number is
Jawaban:
jumlah dari 3 bilangan genap adalah 90 hasil penjumlahan dari bilangan terbesar dan terkecil
2. the sum of 3³ and 9² is
Kelas 6 Matematika
Bab Pangkat Tiga
3³ + 9²
= 27 + 81
= 108
= 4 x 27
= 2² x 3³di artikan jika dijumlahakn 3² dan 9² brp
3³= 27 , 9²= 81
81 ditambah 27 = 108
c. jawabannya . krn 2² =4 dan 3³ =27 = 4 ×27 =108 . sesuai dengan jumlah soal nya
3. find the sum of the value of the digit 4 in 3471 and 4945
Penjelasan dengan langkah-langkah:
digit 4 in 3471 = 400
digit 4 in 4945 = 40
400 + 40 = 440
4. the sum of 461 and 129 is
461+129= 590
moga bantu
5. There are five positive numbers. The sum of the first and the fifth number is 15. the second number is ⅓ of the sum of these five numbers, the third number is ¼ of this sum and the fourth number is 1/5 of this sum. What is the value of the largest number? (Pakai cara)
example : the five positive numbers are a, b, c, d, and e,, the sum = x
a + e = 15
b = 1/3 x
c = 1/4 x
d = 1/5 x
otomatis a = 1/2 x dan e = 1/6 x
1/2 x + 1/6 x = 4/6 x = 2/3 x
a + e = 15
2/3 x = 15
x = 15 : 2/3
= 45/2
the value of the largest number is
a = 1/2 x = 1/2 ( 45/2 ) = 45
=>> 45
maaf kl salah
6. The sum of multiple 3 between 1 and 100 is...
3, 6, ..., 99
a = 3
b = 3
Un = 99
Un = a + (n - 1) b = 99
3 + (n - 1) 3 = 99
(n - 1) 3 = 99 - 3
n - 1 = 96/3
n = 32 + 1
n = 33
Sn = n/2 x (a + Un)
S33 = 33/2 (3 + 99)
S33 = 33/2 x 102
S33 = 33 x 51
S33 = 1.683
7. find the sum of 3/10 and the difference bettwen 3 1/2 and 1 3/5.
Jawaban:
[tex] \frac{3}{10} + (3 \frac{1}{2} - 1 \frac{3}{5} ) = \frac{3}{10} + (2 + \frac{3}{2} - 1 \frac{3 }{5} )[/tex]
[tex] = \frac{3}{10} + (2 - 1 + \frac{15}{10} - \frac{6}{10}) = \frac{3}{10} + 1 \frac{9}{10} [/tex]
[tex] = 1 \frac{12}{10} = 2 \frac{2}{10} = 2 \frac{1}{5} [/tex]
8. The sum of 4 cunsencentive and odd number is 64. Find the largest of 4 numbers
Let, the middle number in the sequence be X.
So, the sequence of five consecutive odd numbers will be,
(X-2),(X-1),X,(X+1),(X+2)
Now, the sum of 64 consecutive odd numbers is 64
So,
(X-2)+(X-1)+X+(X+1)+(X+2)= 64
4X = 64
X = 64/4
X = 16
Find the largest number
= X+2
= 16+2
= 18
So, the largest number in the sequence will be 18.
9. Write an algebric expression for each verbal expression. Then simplify, indicating the properties used 1. the product of 9 and t squared, increased by the sum of the square of t and 22. 3 times the sum of r and d squared minus 2 times the sum of r and d squared
Subject : Pre-algebra
Category : Algebraic expression
Answers :
1. (9 * t)² + (t + 2)²
= 81t² + t² + 4t + 4
= 82t² + 4t + 4
2. 3(r + d)² - 2(r + d)²
= (r + d)²
= r² + 2rd + d²
--------------------------------------------------------------
Explanation:
the product of = hasil perkalian dari
squared = pangkat 2
increased by = ditambah dengan
the sum of = hasil penjumlahan dari
the square of = pemangkatan 2 dari
times = kali (x)
minus = kurang
10. Find the sum of 460 and 75.
Jawaban:
460
75 +
535
Penjelasan dengan langkah-langkah:
......................
11. kak tolong translate ke dalam angka1. the sum of five times h and twice g is equal to 232. one fourth the sum of r and ten is identical to r minus 43. three plus the sum of the squares of w and x is 32
1. 5h+2g=23
2. 1/4(r+10)=r-4
r+10=4r-16
r=-26/3
3. 3(w^2+x)=32
3w^2+x=32
12. if the sum of the 2nd and 8th terms is 40 and the sum of the 3rd and 6th terms is 36, what is 5th terms?
Jawaban:
maaf kuarang jelas coba transelete ke indo
13. Find the sum of 803 and 349.
Jawab:
1152
Penjelasan dengan langkah-langkah:
803
349
____ _
1152
JAWABAN :
1152
803+349 = 1152
14. 4. Divide the sum of 34 and 20 by 6.
Penjelasan dengan langkah-langkah:
[tex] \frac{34 + 20}{6} = \frac{54}{6} = 9[/tex]
The sum of 34 and 20, and then divided by 6 is 9
.
PembahasanDi dalam pengerjaan soal matematika, kita harus memperhatikan prioritas atau urutan di dalam mengerjakan soal atau pertanyaan matematika. Sistem prioritas ini harus terus digunakan untuk seluruh soal matematika, karena jika kita tidak menggunakansistem ini, maka hasil yang diperoleh akan kurang akurat atau dapat dikatakan salah.
.
Sistem prioritas di dalam pengerjaan soal matematika kurang lebih seperti ini:
Mengerjakan terlebih dahulu operasi yang berada di dalam tanda kurung, baik itu penjumlahan ataupun pengurangan, tetap saja operasi yang berada di dalam kurung harus dikerjakan terlebih dahuluMengerjakan perkalian ataupun pembagian secara urut dari arah paling kiri ke arah kanan.Yang terakhir adalah mengerjakan penjumlahan ataupun pengurangan secara urut dari kiri ke kanan..
Pada bilangan bulat terdapat 2 sifat bilangan, yaitu negatif (-) dan positif (+). Kedua sifat ini dapat mempengaruhi operasi bilangan tersebut, maupun hasilnya juga. Contohnya dari perubahan operasi bilangan yang disebabkan oleh sifat bilangan, yaitu:
[tex]x - ( - y) = x + y[/tex]
[tex]x + ( - y) = x - y[/tex]
[tex] - x - y = - (x + y)[/tex]
[tex] - x + y = y + ( - x) = y - x[/tex]
.
Contoh perubahan hasil dari operasi yang disebabkan oleh sifat bilangan, yaitu:
[tex] - x \times ( - y) = xy[/tex]
[tex] - x \times y = - xy[/tex]
[tex]x \times ( - y) = - xy[/tex]
[tex] - x \div ( - y) = \frac{ - x}{ - y} = \frac{x}{y} [/tex]
[tex] - x \div y = - \frac{x}{y} [/tex]
[tex] x \div ( - y) = - \frac{x}{y} [/tex]
.
PenyelesaianDiketahui[tex](34 + 20) \div 6 = [/tex]
.
DitanyaThe sum of 34 and 20, and then divided by 6 is...
.
Jawaban[tex] = (34 + 20) \div 6[/tex]
[tex] = 54 \div 6[/tex]
[tex] = 9[/tex]
.
So, the sum of 34 and 20, and then divided by 6 is 9
.
Pelajari Lebih LanjutMateri mengenai operasi hitung bilangan bulat dapat dipelajari di link berikut:
Contoh soal perkalian dan pembagian pada bilangan bulat: brainly.co.id/tugas/33404515Contoh soal operasi penjumlahan dan pengurangan pada bilangan bulat: brainly.co.id/tugas/18270720Contoh soal operasi hitung campuran: brainly.co.id/tugas/17146586Materi mengenai operasi perkalian pada bilangan bulat: brainly.co.id/tugas/23319897.
===================================
Detail JawabanKelas: 6
Mapel: Matematika
Kategori: Operasi hitung bilangan bulat
Kode: 6.2.1
Kata kunci: Perkalian, pembagian, penjumlahan, pengurangan, sistem prioritas, positif, negatif
15. The sum of two numbers is 20 and the sum of their squares is 272. Find the firstnumber
Jawab:
4 or 16
Penjelasan dengan langkah-langkah:
Let the numbers be x and y
x + y = 20
sum of their squares is 272 so x^2 + y^2 = 272
Find the first number,
We know that x^2 + y^2 = (x + y)^2 - 2xy
so 272 = 20^2 - 2xy
272 = 400 - 2xy
2xy = 128
xy = 64
We know that x + y = 20 and xy = 64, so we can make quadratic equation,
let a1 = x and a2 = y
a^2 - 20a + 64 = 0
(a - 16)(a - 4) = 0
a = 16 or a = 4
So the first number can be 4 or 16
If the first number less than the second, the answer is 4
Semoga terbantu :)
IG: @djie.jemmy
Jawab:
4 or 16Penjelasan dengan langkah-langkah:
If the first number is [tex]x[/tex] and the second one is [tex]y[/tex],
we can write:
[tex]x + y = 20[/tex]
[tex]x^{2} + y^{2} = 272[/tex]
Then
[tex]x = 20 - y[/tex]
Substitute [tex]x = 20 - y[/tex] to [tex]x^{2} + y^{2} = 272[/tex]
[tex](20 - y)^{2} + y^{2} = 272[/tex]
[tex]400 - 40y + y^{2} + y^{2} = 272[/tex]
[tex]2y^{2} - 20y + 128 = 0[/tex]
Factorize the equation and we get:
[tex](y-16)(y-4) = 0[/tex]
[tex]y = 16[/tex] ∨[tex]y = 4[/tex]
If we substitute [tex]y = 16[/tex] to [tex]x = 20 - y[/tex], we get [tex]x = 4[/tex]
So, we can conclude that both numbers are 4 and 16.
16. The sum of 438 and 241 Is
Jawaban:
438 + 241 = 679
Semoga membantu :)
17. apter 9 Review(a) Find the sum of , and3
Jawaban:
aku tidak mengerti
Penjelasan dengan langkah-langkah:
wokwokwokwok
18. Find the sum of 2/3 and 1/9! tolongin:''
Penjelasan dengan langkah-langkah:
[tex] \frac{2}{3} + \frac{1}{9} = \\ \frac{6}{9} + \frac{1}{9} = \\ \frac{7}{9} [/tex]
19. the sum of the first and ninth term of an arithmetic progression is 24.find the sum of the first nine terms of this progression
semoga membantu. maaf, jika salah
20. find the sum of all multiples of 3 between 50 and 100
Jawab:
1125
Penjelasan dengan langkah-langkah:
a = 51
U15 = 99
[tex]S_n=\frac{n}{2} (a+U_n )\\S_15=\frac{15}{2} (51+99 )=1125[/tex]
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